奇门遁甲演义V6.3破解手记--注册码算法分析 -pc6资讯

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奇门遁甲演义V6.3破解手记--注册码算法分析 时间：2004/10/15 0:53:00来源：本站整理作者：蓝点我要评论(0): 　

奇门遁甲演义V6.3破解手记--注册码算法分析
作者：newlaos[DFCG]

软件名称：奇门遁甲演义V6.3(周易)
文件大小：2360KB(软件做好后，没有做任何处理，建议作者有类似UPX将软件压缩一下)
软件授权：共享软件
使用平台：Win9x/Me/NT/2000/XP
发布公司："http://www.380000.com/
软件简介：自动排出从1900年到2050年内的任意时间的时家、日家、月家、年家奇门遁甲局况；附有相应的古注语和现注解，用彩色标出其中常见的凶格和吉格；方便的时间查找功能，自动查找满足输入条件的时间；可以导出局图的纯文字版本，方便复制和传播；时间调整功能；更详细的帮助文档。

加密方式：注册码
功能限制：频繁弹出注册对话框
PJ工具：TRW20001.23注册版、W32Dasm8.93黄金版，FI2.5
PJ日期：2003-03-23
作者newlaos申明：只是学习，请不用于商业用途或是将本文方法制作的注册机任意传播，造成后果，本人一概不负。

1、先用FI2.5看一下主程序“奇门遁甲演义VI.exe”，没有加壳。是用VB编写的。

2、用W32Dasm8.93黄金版对主文件进行静态反汇编，再用串式数据参考，找到"注册成功！"(很经典的句子)，双击来到下面代码段。这样就找到注册码的计算部分。

3、再用TRW20001.23注册版进行动态跟踪，下断BPX 0040B73E(通常在注册成功与否的前面一些下断，这样，才能找到关键部分)，先输入假码78787878

.......
.......
:0040B73E FF15C4D14100 Call dword ptr [0041D1C4]
:0040B744 A1D0D64100 mov eax, dword ptr [0041D6D0]
:0040B749 8D4C2448 lea ecx, dword ptr [esp+48]
:0040B74D 50 push eax

* Possible Reference to String Resource ID=00002: "212112121222#8"
|
:0040B74E 6A02 push 00000002

* Possible StringData Ref from Data Obj ->"register.ini"
|
:0040B750 68782D4200 push 00422D78 <===文件里放了只有我们输入的假码(78787878)
:0040B755 E816830000 call 00413A70
:0040B75A 8D7C2408 lea edi, dword ptr [esp+08]
:0040B75E 83C9FF or ecx, FFFFFFFF
:0040B761 33C0 xor eax, eax
:0040B763 F2 repnz
:0040B764 AE scasb
:0040B765 F7D1 not ecx
:0040B767 49 dec ecx
:0040B768 51 push ecx
:0040B769 8D4C240C lea ecx, dword ptr [esp+0C]
:0040B76D 51 push ecx
:0040B76E 8D4C2450 lea ecx, dword ptr [esp+50]
:0040B772 E835830000 call 00413AAC
:0040B777 8D4C2448 lea ecx, dword ptr [esp+48]
:0040B77B E8827E0000 call 00413602
:0040B780 8B0D643F4200 mov ecx, dword ptr [00423F64]
:0040B786 E8F5020000 call 0040BA80 <===这个CALL会改变88FCA4处的值(这是一个标志位)，所以F8跟进
:0040B78B 8B15643F4200 mov edx, dword ptr [00423F64]
:0040B791 5F pop edi
:0040B792 8A8228A40000 mov al, byte ptr [edx+0000A428]
<===EDX=88587C(在88FCA4处的值很关键, 不能为0)
:0040B798 84C0 test al, al <===要不为0，才能正确跳转
:0040B79A 7515 jne 0040B7B1 <===关键跳转，跳才正确

* Possible Reference to String Resource ID=00016: "221212212121#3"
|
:0040B79C 6A10 push 00000010

* Possible StringData Ref from Data Obj ->"错误"
|
:0040B79E 6874004200 push 00420074

* Possible StringData Ref from Data Obj ->"注册失败！"
|
:0040B7A3 686C2D4200 push 00422D6C
:0040B7A8 56 push esi

* Reference To: USER32.MessageBoxA, Ord:01BEh
|
:0040B7A9 FF1580D14100 Call dword ptr [0041D180]
:0040B7AF EB78 jmp 0040B829

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B79A(C)
|

* Possible Reference to String Resource ID=00064: "212112121222#13"
|
:0040B7B1 6A40 push 00000040

* Possible StringData Ref from Data Obj ->"提示"
|
:0040B7B3 68FC2C4200 push 00422CFC

* Possible StringData Ref from Data Obj ->"注册成功！"
|
:0040B7B8 68602D4200 push 00422D60
:0040B7BD 56 push esi

* Reference To: USER32.MessageBoxA, Ord:01BEh
|
:0040B7BE FF1580D14100 Call dword ptr [0041D180]
:0040B7C4 A1643F4200 mov eax, dword ptr [00423F64]
:0040B7C9 6A00 push 00000000
:0040B7CB 56 push esi
:0040B7CC C78004A40000FA000000 mov dword ptr [ebx+0000A404], 000000FA

* Reference To: USER32.EndDialog, Ord:00B9h
|
:0040B7D6 FF15DCD14100 Call dword ptr [0041D1DC]
:0040B7DC EB4B jmp 0040B829
.......
.......

-----0040B786 call 0040BA80 我们按F8跟进来到下面代码段-------
这一段的功能：是把我的注册码以“-”为标志分成5串，而后与机器生成的5串依次比较，只一次错就跳出
:0040BA80 6AFF push FFFFFFFF
:0040BA82 6858BB4100 push 0041BB58
:0040BA87 64A100000000 mov eax, dword ptr fs:[00000000]
:0040BA8D 50 push eax
:0040BA8E 64892500000000 mov dword ptr fs:[00000000], esp
:0040BA95 81EC80000000 sub esp, 00000080
:0040BA9B 55 push ebp
:0040BA9C 8BE9 mov ebp, ecx
:0040BA9E 57 push edi

* Possible Reference to String Resource ID=00001: "121121212221#19"
|
:0040BA9F 6A01 push 00000001
:0040BAA1 8D4C244C lea ecx, dword ptr [esp+4C]
:0040BAA5 E8587A0000 call 00413502

* Possible Reference to String Resource ID=00007: "121212212121#13"
|
:0040BAAA B907000000 mov ecx, 00000007
:0040BAAF 33C0 xor eax, eax
:0040BAB1 8D7C2428 lea edi, dword ptr [esp+28]
:0040BAB5 6A00 push 00000000
:0040BAB7 F3 repz
:0040BAB8 AB stosd

* Possible StringData Ref from Data Obj ->"register.ini"
|
:0040BAB9 68782D4200 push 00422D78
:0040BABE C784249800000000000000 mov dword ptr [esp+00000098], 00000000
:0040BAC9 66AB stosw
:0040BACB E879FC0000 call 0041B749
:0040BAD0 83C408 add esp, 00000008
:0040BAD3 83F8FF cmp eax, FFFFFFFF
:0040BAD6 0F84CC000000 je 0040BBA8 <===这是不能跳，跳过去就OVER了。
:0040BADC A1D0D64100 mov eax, dword ptr [0041D6D0]
:0040BAE1 8D4C2448 lea ecx, dword ptr [esp+48]
:0040BAE5 50 push eax

* Possible Reference to String Resource ID=00001: "121121212221#19"
|
:0040BAE6 6A01 push 00000001

* Possible StringData Ref from Data Obj ->"register.ini"
|
:0040BAE8 68782D4200 push 00422D78
:0040BAED E8D47A0000 call 004135C6
:0040BAF2 8B54244C mov edx, dword ptr [esp+4C]

* Possible Reference to String Resource ID=00010: "121121212221#10"
|
:0040BAF6 6A0A push 0000000A
:0040BAF8 8D4C242C lea ecx, dword ptr [esp+2C]

* Possible Reference to String Resource ID=00030: "1221123121221#30"
|
:0040BAFC 6A1E push 0000001E
:0040BAFE 42 inc edx
:0040BAFF 51 push ecx
:0040BB00 8D4C2454 lea ecx, dword ptr [esp+54]
:0040BB04 89542458 mov dword ptr [esp+58], edx
:0040BB08 E8E27F0000 call 00413AEF
:0040BB0D 8D4C2448 lea ecx, dword ptr [esp+48]
:0040BB11 E8EC7A0000 call 00413602
:0040BB16 8BCD mov ecx, ebp
:0040BB18 E8A3FDFFFF call 0040B8C0
:0040BB1D 8D542414 lea edx, dword ptr [esp+14]
:0040BB21 89442408 mov dword ptr [esp+08], eax
:0040BB25 52 push edx
:0040BB26 8D44242C lea eax, dword ptr [esp+2C]

* Possible Reference to String Resource ID=00045: "112112122212#13"
|
:0040BB2A 6A2D push 0000002D
:0040BB2C 50 push eax
:0040BB2D 8BCD mov ecx, ebp
:0040BB2F E8FC4F0000 call 00410B30 <===这个CALL主要功能是看输入的注册码里有没有五个“-”字符，到这里我们将假码改为78-78-78-78-78-78，重新来(为了说明方便，我们定义为注册码的1、2、3、4、5串)
:0040BB34 83F805 cmp eax, 00000005 <===EAX必须等于5，否则就跳走出错了。
:0040BB37 756F jne 0040BBA8
<===因为跳到错的地方有两个，上面那不会跳，所以这里是一个很关键的跳转
:0040BB39 53 push ebx
:0040BB3A 56 push esi
:0040BB3B 33FF xor edi, edi <===EDI是个计数器，共5次，对应注册码有5串
:0040BB3D 8D5C241C lea ebx, dword ptr [esp+1C]

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040BB8D(C)
|
:0040BB41 8B542410 mov edx, dword ptr [esp+10]
:0040BB45 8D4C2414 lea ecx, dword ptr [esp+14]
:0040BB49 51 push ecx
:0040BB4A 57 push edi
:0040BB4B 52 push edx
:0040BB4C 8BCD mov ecx, ebp
:0040BB4E E89DFDFFFF call 0040B8F0 <===呵呵，这个就是算出正确的串值的CALL了。F8跟进
:0040BB53 8B33 mov esi, dword ptr [ebx]
:0040BB55 8D442414 lea eax, dword ptr [esp+14]
<===我的机器出现EAX=为正确的串值(这里用于比较的)，共5次，在这里设断，得到一个值就将它改为注册码的对应的串，再点注册，又失败，但得到下一串的值，如此循环，注册失败5次后，你就得到全部的注册码了，我的是PLT6D-1DNLD-1KFDD-0XXXX-PLSCG

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040BB77(C)
|
:0040BB59 8A10 mov dl, byte ptr [eax]
:0040BB5B 8ACA mov cl, dl
:0040BB5D 3A16 cmp dl, byte ptr [esi]
:0040BB5F 751C jne 0040BB7D
:0040BB61 84C9 test cl, cl
:0040BB63 7414 je 0040BB79
:0040BB65 8A5001 mov dl, byte ptr [eax+01]
:0040BB68 8ACA mov cl, dl
:0040BB6A 3A5601 cmp dl, byte ptr [esi+01]
:0040BB6D 750E jne 0040BB7D
:0040BB6F 83C002 add eax, 00000002
:0040BB72 83C602 add esi, 00000002
:0040BB75 84C9 test cl, cl
:0040BB77 75E0 jne 0040BB59
<===这里构成一个小循环功能是把我们输入的假码以“-”字符分开的字符与在0040BB55给出的EAX值作比较，只要一处错就跳到40BB7D，就OVER了。

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040BB63(C)
|
:0040BB79 33C0 xor eax, eax
:0040BB7B EB05 jmp 0040BB82

* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0040BB5F(C), :0040BB6D(C)
|
:0040BB7D 1BC0 sbb eax, eax <===(带位减法)EAX清0
:0040BB7F 83D8FF sbb eax, FFFFFFFF <===EAX=1

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040BB7B(U)
|
:0040BB82 85C0 test eax, eax
<===EAX=1说明上面循环比较出错了，EAX=0就说明比较对了。
:0040BB84 750B jne 0040BB91 <===如果EAX=1，这里再跳走，EAX=0不跳
:0040BB86 47 inc edi
:0040BB87 83C304 add ebx, 00000004
:0040BB8A 83FF05 cmp edi, 00000005
:0040BB8D 7CB2 jl 0040BB41
<===这里是个大循环，共5次，分别比较机器算出的5个串和我们输入的5个串做比较。
:0040BB8F EB07 jmp 0040BB98 <===5次循环都正确，就到这里再跳向胜利。

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040BB84(C)
|
:0040BB91 C68528A4000000 mov byte ptr [ebp+0000A428], 00

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040BB8F(U)
|
:0040BB98 5E pop esi
:0040BB99 83FF05 cmp edi, 00000005
<===这里也是一个很关键的对比，上面0040BB91已经把标志位清0
:0040BB9C 5B pop ebx
:0040BB9D 7510 jne 0040BBAF <===如果这里跳走，就OVER
:0040BB9F C68528A4000001 mov byte ptr [ebp+0000A428], 01
<===[ebp+0000A428]是个标志位，能到这里，说明成功
:0040BBA6 EB07 jmp 0040BBAF

* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0040BAD6(C), :0040BB37(C)
|
:0040BBA8 C68528A4000000 mov byte ptr [ebp+0000A428], 00
<===[ebp+0000A428]是个标志位，要是到这里，说明失败
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0040BB9D(C), :0040BBA6(U)
|
:0040BBAF 8D4C2454 lea ecx, dword ptr [esp+54]
:0040BBB3 C7842490000000FFFFFFFF mov dword ptr [esp+00000090], FFFFFFFF
:0040BBBE E8F0790000 call 004135B3
:0040BBC3 8D4C2454 lea ecx, dword ptr [esp+54]
:0040BBC7 E8DE780000 call 004134AA
:0040BBCC 8B8C2488000000 mov ecx, dword ptr [esp+00000088]
:0040BBD3 5F pop edi
:0040BBD4 5D pop ebp
:0040BBD5 64890D00000000 mov dword ptr fs:[00000000], ecx
:0040BBDC 81C48C000000 add esp, 0000008C
:0040BBE2 C3 ret

-----0040BB4E call 0040B8F0 这个就是算出正确的串值的CALL了---------------
我的注册码机器454376902，注册码就是PLT6D-1DNLD-1KFDD-0XXXX-PLSCG
* Referenced by a CALL at Address:
|:0040BB4E
|
:0040B8F0 83EC18 sub esp, 00000018
:0040B8F3 33C0 xor eax, eax <===每次进来EAX都要清0
:0040B8F5 53 push ebx
:0040B8F6 8B5C2428 mov ebx, dword ptr [esp+28]
:0040B8FA 8BCB mov ecx, ebx
:0040B8FC 56 push esi
:0040B8FD 57 push edi
:0040B8FE 8901 mov dword ptr [ecx], eax
:0040B900 66894104 mov word ptr [ecx+04], ax
:0040B904 E8B68F0000 call 004148BF
:0040B909 99 cdq

* Possible Reference to String Resource ID=00100: "221121121221#5"
|
:0040B90A B964000000 mov ecx, 00000064
:0040B90F F7F9 idiv ecx <===整数除法(EAX/ECX)，商回EAX，余数回ECX
:0040B911 33C0 xor eax, eax
:0040B913 85D2 test edx, edx
:0040B915 7E14 jle 0040B92B
:0040B917 8B4C2428 mov ecx, dword ptr [esp+28]

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B929(C)
|
:0040B91B 85C0 test eax, eax
:0040B91D 7405 je 0040B924
:0040B91F 0FAFC8 imul ecx, eax
:0040B922 EB02 jmp 0040B926

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B91D(C)
|
:0040B924 8BCA mov ecx, edx

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B922(U)
|
:0040B926 40 inc eax
:0040B927 3BC2 cmp eax, edx
:0040B929 7CF0 jl 0040B91B <===这里是一个循环结构

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B915(C)
|
:0040B92B 8B44242C mov eax, dword ptr [esp+2C] <===从EAX=0开始，每次循环到里，就加1，最后
:0040B92F 83F804 cmp eax, 00000004 <===最后EAX=4，退出，共循环5次，正好是注册码的5个串值
:0040B932 7761 ja 0040B995
:0040B934 FF248560BA4000 jmp dword ptr [4*eax+0040BA60]
<===注意由于每次EAX都加1，所以导致这个无条件跳转到的位置不同，每次不同跳转产生不同的值共同构成这个注册码。

:0040B93B 8B442428 mov eax, dword ptr [esp+28]
<===第一次跳到这里，EAX=1B153DC6 ,它的十进制是454376732，正好是我的机器码!
:0040B93F 3503008519 xor eax, 19850003 <===1B153DC6与19850003做异或运算
:0040B944 0D34120000 or eax, 00001234 <===EAX再与1234做或运算，值放入EAX(为说明问题，我们定义为EAX1)
:0040B949 EB4E jmp 0040B999 <===跳走
:0040B94B 8B442428 mov eax, dword ptr [esp+28]
<===第二次跳到这里，EAX=1B153DC6,它的十进制是454376732，正好是我的机器码!

* Possible Reference to String Resource ID=00001: "121121212221#19"
|
:0040B94F B901000000 mov ecx, 00000001 <===ECX初始化为1，计数器

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B95D(C)
|
:0040B954 8BD1 mov edx, ecx
:0040B956 0FAFC2 imul eax, edx <===但实际动态跟踪时发现是EAX=EAX*1*2*3*4*5*6*7*8*9*A*B*C*D*E*F*10*11*12*13
:0040B959 41 inc ecx <===ECX=ECX+1
:0040B95A 83F913 cmp ecx, 00000013
:0040B95D 7EF5 jle 0040B954 <===共循环16(注13是十六进制)次。
:0040B95F 0D34120000 or eax, 00001234 <===EAX再与1234做或运算，值放入EAX(为说明问题，我们定义为EAX2)
:0040B964 EB33 jmp 0040B999 <===跳走
:0040B966 8B442428 mov eax, dword ptr [esp+28]
<===第三次跳到这里，EAX=1B153DC6,它的十进制是454376732，正好是我的机器码!
:0040B96A 69C03C642B01 imul eax, 012B643C <===EAX=EAX*12B643C
:0040B970 0D34120000 or eax, 00001234 <===EAX再与1234做或运算，值放入EAX(为说明问题，我们定义为EAX3)
:0040B975 EB22 jmp 0040B999 <===跳走
:0040B977 8B442428 mov eax, dword ptr [esp+28]
<===第四次跳到这里，EAX=1B153DC6,它的十进制是454376732，正好是我的机器码!
* Possible Reference to String Resource ID=00010: "121121212221#10"
|
:0040B97B B90A000000 mov ecx, 0000000A <===将ECX初始化为10，

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B986(C)
|
:0040B980 8BD0 mov edx, eax
:0040B982 0FAFC2 imul eax, edx
<===最后(EAX的值用C语言表示)
eax=1B153DC6;
for(i=0;i<>10;i++)
{eax=eax^2;
}
:0040B985 49 dec ecx <===ECX=ECX-1
:0040B986 75F8 jne 0040B980 <===共一个小的循环结构，共循环10次，后退出!
:0040B988 EB0F jmp 0040B999 <===跳走，这里的EAX(为说明问题，我们定义为EAX4)
:0040B98A 8B442428 mov eax, dword ptr [esp+28]
:0040B98E 3506068519 xor eax, 19850606
:0040B993 EB04 jmp 0040B999

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B932(C)
|
:0040B995 8B442428 mov eax, dword ptr [esp+28]
<===第五次跳到这里，EAX=1B153DC6,它的十进制是454376732，正好是我的机器码!。这里EAX不再做任何处理，直接拿来用了。(为说明问题，我们定义为EAX5)
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0040B949(U), :0040B964(U), :0040B975(U), :0040B988(U), :0040B993(U)
|
:0040B999 8D4C240C lea ecx, dword ptr [esp+0C]

* Possible Reference to String Resource ID=00036: "2114112212221#24"
|
:0040B99D 6A24 push 00000024
:0040B99F 51 push ecx <====ECX=8850D8
:0040B9A0 50 push eax
<====这里的EAX1，EAX2，EAX3，EAX4，EAX5分别为2903FF5，B2F61234，CB5DD27，0000000，2903BC0
:0040B9A1 E879FD0000 call 0041B71F <===这里面，EAX1，EAX2，EAX3，EAX4，EAX5再进行处理，就生成最终对应的串值，并放在出来的EAX中，F8跟进
:0040B9A6 8D7C2418 lea edi, dword ptr [esp+18]
:0040B9AA 83C9FF or ecx, FFFFFFFF
:0040B9AD 33C0 xor eax, eax
:0040B9AF 83C40C add esp, 0000000C
:0040B9B2 F2 repnz
:0040B9B3 AE scasb
:0040B9B4 F7D1 not ecx
:0040B9B6 49 dec ecx
:0040B9B7 8BF1 mov esi, ecx
:0040B9B9 33C9 xor ecx, ecx
:0040B9BB 85F6 test esi, esi
:0040B9BD 7E17 jle 0040B9D6

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B9D4(C)
|
:0040B9BF 8A440C0C mov al, byte ptr [esp+ecx+0C]
:0040B9C3 3C61 cmp al, 61
:0040B9C5 7C0A jl 0040B9D1
:0040B9C7 3C7A cmp al, 7A
:0040B9C9 7F06 jg 0040B9D1
:0040B9CB 2C20 sub al, 20
:0040B9CD 88440C0C mov byte ptr [esp+ecx+0C], al

* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0040B9C5(C), :0040B9C9(C)
|
:0040B9D1 41 inc ecx
:0040B9D2 3BCE cmp ecx, esi
:0040B9D4 7CE9 jl 0040B9BF

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0040B9BD(C)
|
:0040B9D6 83FE05 cmp esi, 00000005
:0040B9D9 7C1C jl 0040B9F7
:0040B9DB 8D54240C lea edx, dword ptr [esp+0C]
:0040B9DF 52 push edx

* Possible StringData Ref from Data Obj ->"%.5s"
|
:0040B9E0 68F82D4200 push 00422DF8
:0040B9E5 53 push ebx
:0040B9E6 E8EE890000 call 004143D9
:0040B9EB 83C40C add esp, 0000000C
:0040B9EE 5F pop edi
:0040B9EF 5E pop esi
:0040B9F0 5B pop ebx
:0040B9F1 83C418 add esp, 00000018
:0040B9F4 C20C00 ret 000C

---------:0040B9A1 call 0041B71F 按F8跟进来到下面代码段--------------------
这段代码的作用：将EAX1，EAX2，EAX3，EAX4，EAX5再进行处理，就生成最终对应的串值，并放在出来的EAX中

* Referenced by a CALL at Addresses:
|:0040B80D , :0040B9A1
|
:0041B71F 55 push ebp
:0041B720 8BEC mov ebp, esp
:0041B722 33C0 xor eax, eax
:0041B724 837D100A cmp dword ptr [ebp+10], 0000000A <===[EBP+10]每次都是24
:0041B728 7508 jne 0041B732 <===所以这里每次跳走
:0041B72A 394508 cmp dword ptr [ebp+08], eax
:0041B72D 7D03 jge 0041B732

* Possible Reference to String Resource ID=00001: "121121212221#19"
|
:0041B72F 6A01 push 00000001
:0041B731 58 pop eax

* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0041B728(C), :0041B72D(C)
|
:0041B732 50 push eax
:0041B733 FF7510 push [ebp+10] <===跳到这里，将24(十六进制)压入栈
:0041B736 FF750C push [ebp+0C] <===将8850D8压入栈，这个是最终串值返回时的地址
:0041B739 FF7508 push [ebp+08] <===依次将EAX1，EAX2，EAX3，EAX4，EAX5压入栈
:0041B73C E882FFFFFF call 0041B6C3 <===这个CALL出来，EAX里就是正确的串值了，F8再跟进
:0041B741 8B450C mov eax, dword ptr [ebp+0C] <===最终将正确的串值放入EAX中
:0041B744 83C410 add esp, 00000010
:0041B747 5D pop ebp
:0041B748 C3 ret

---------:0041B73C call 0041B6C3 按F8跟进来到下面代码段--------------------
这段代码的作用：将EAX1，EAX2，EAX3，EAX4，EAX5再进行处理，就生成最终对应的串值，并放在出来的EAX中

* Referenced by a CALL at Addresses:
|:0041B6B6 , :0041B73C
|
:0041B6C3 55 push ebp
:0041B6C4 8BEC mov ebp, esp
:0041B6C6 837D1400 cmp dword ptr [ebp+14], 00000000 <===这里5次都相等
:0041B6CA 8B4D0C mov ecx, dword ptr [ebp+0C]
:0041B6CD 53 push ebx
:0041B6CE 56 push esi
:0041B6CF 57 push edi
:0041B6D0 740B je 0041B6DD <===这里5次都跳走
:0041B6D2 8B7508 mov esi, dword ptr [ebp+08]
:0041B6D5 C6012D mov byte ptr [ecx], 2D
:0041B6D8 41 inc ecx
:0041B6D9 F7DE neg esi
:0041B6DB EB03 jmp 0041B6E0

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0041B6D0(C)
|
:0041B6DD 8B7508 mov esi, dword ptr [ebp+08] <===跳到这里，ESI=EAX(1，2，3，4，5)

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0041B6DB(U)
|
:0041B6E0 8BF9 mov edi, ecx <===EDI=8850D8

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0041B706(C)
|
:0041B6E2 8BC6 mov eax, esi <===EAX=EAX(1，2，3，4，5)
:0041B6E4 33D2 xor edx, edx <===将EDX清0
:0041B6E6 F77510 div [ebp+10] <===将EAX(1，2，3，4，5)除以24，商回EAX，余数回EDX
:0041B6E9 8BC6 mov eax, esi <===EAX=EAX(1，2，3，4，5)
:0041B6EB 8BDA mov ebx, edx <===EBX=余数
:0041B6ED 33D2 xor edx, edx <===将EDX清0
:0041B6EF F77510 div [ebp+10] <===将EAX(1，2，3，4，5)除以24(十六进制)，商回EAX，余数回EDX(不明白为什么又除一遍)
:0041B6F2 83FB09 cmp ebx, 00000009 <===这个判断很重要!
:0041B6F5 8BF0 mov esi, eax
:0041B6F7 7605 jbe 0041B6FE <===如果余数是数字，就跳转。如果余数是字符，就不跳转
:0041B6F9 80C357 add bl, 57
:0041B6FC EB03 jmp 0041B701

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0041B6F7(C)
|
:0041B6FE 80C330 add bl, 30

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0041B6FC(U)
|
:0041B701 8819 mov byte ptr [ecx], bl <===其实这个判断的处理作用就是将余数处理为其对应的ASCII值(字符是小写)
:0041B703 41 inc ecx
:0041B704 85F6 test esi, esi
:0041B706 77DA ja 0041B6E2 <===从这里向上，构成一个循环结构，共循环5次，第n次在bl处得到余数转为字符后，就构成串值的第n位
***** 这一小段的循环作用(以EAX1为例)：
公式商余数对应的字符
2903FF5/24 123AAA D d
123AAA/24 81A1 6 6
81A1/24 339 1D t (d字符后面的16位的字符)以ASC码表为顺序
339/24 19 15 l (数字5后面的16位的字符)
19/24 0 19 p (数字9后面的16位的字符)
***** 最后在内存的8850D8位置上得到串值d6tlp

:0041B708 802100 and byte ptr [ecx], 00
:0041B70B 49 dec ecx

* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0041B718(C)
|
:0041B70C 8A17 mov dl, byte ptr [edi]
:0041B70E 8A01 mov al, byte ptr [ecx]
:0041B710 8811 mov byte ptr [ecx], dl
:0041B712 8807 mov byte ptr [edi], al
:0041B714 49 dec ecx
:0041B715 47 inc edi
:0041B716 3BF9 cmp edi, ecx
:0041B718 72F2 jb 0041B70C
<===从这里向上，构成一个循环结构，作用是将上面得到串值反向再取值，所以最后8850D8位置上得到串值plt6d(其它程序段会把它转为大写)
:0041B71A 5F pop edi
:0041B71B 5E pop esi
:0041B71C 5B pop ebx
:0041B71D 5D pop ebp
:0041B71E C3 ret
此段总结：依照上面的步骤将EAX1，EAX2，EAX3，EAX4，EAX5最后处理为plt6d,1dnld,1kfdd,0xxxx,plscg ----注册码浮出水面

-------------------------------------------------------------------------------------------------

4、算法总结：-----类型：f(机器码)=注册码------
a、将机器码454376732(每台机器码都不一样)，转换为十六进制1B153DC6

b、将1B153DC6分别做5种的处理，得到相应串值的第一次变形
第一种处理：1B153DC6与19850003做异或运算，再与1234做或运算，得到2903FF5
第二种处理：1B153DC6EAX=EAX*1*2*3*4*5*6*7*8*9*A*B*C*D*E*F*10*11*12*13，再与1234做或运算，得到B2F61234
第三种处理：1B153DC6*12B643C，再与1234做或运算，得到CB5DD27C
第四种处理：eax=1B153DC6; for(i=0;i<>10;i++) {eax=eax^2;}一般情况EAX都会因为值太大，而爆为00000000
第五种处理：1B153DC6不做处理

c、分别将上一步得到的5串数字，做同样的处理，也就是(以EAX1为例)：
公式商余数对应的字符
2903FF5/24 123AAA D d
123AAA/24 81A1 6 6
81A1/24 339 1D t (d字符后面的16位的字符)以ASC码表为顺序
339/24 19 15 l (数字5后面的16位的字符)
19/24 0 19 p (数字9后面的16位的字符)
最后改为字符串d6tlp，其它的四个串也依次类推。

d、将上一步得到的5个字符分别反向取值，分别得到plt6d,1dnld,1kfdd,0xxxx,plscg，最后的注册码就是将它转为大写后，中间分别加上“-”，PLT6D-1DNLD-1KFDD-0XXXX-PLSCG

5、注册信息存放在奇门遁甲演义V6.3所在目录的register.ini文件中。以明文件形式保留。

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